What is the theoretical yield of aluminum that can be produced by the reaction of 60.0 g of aluminum oxide with 30.0 g of carbon according to the following chemical reaction? Al₂O₃ + 3C $\rarr$ 2Al + 3CO

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Quizplus · Accepted Answer

The limiting reactant is Al₂O₃. The molar mass of Al₂O₃ is 101.96 g/mol, so 60.0 g is 0.588 mol. The reaction produces 2 moles of Al per mole of Al₂O₃, so 0.588 mol of Al₂O₃ produces 1.176 mol of Al. The molar mass of Al is 26.98 g/mol, so the theoretical yield is 1.176 mol × 26.98 g/mol = 31.8 g.

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