Based on the solubility rules, which of the following will occur when a solution containing about 0.1 g of Pb(NO₃)₂(aq)is mixed with a solution containing 0.1 g of KI(aq)/100 mL? A)KNO₃ will precipitate; Pb²⁺ and I^- are spectator ions. B)No precipitate will form. C)Pb(NO₃)₂ will precipitate; K⁺ and I^- are spectator ions. D)PbI₂ will precipitate; K⁺ and NO₃^- are spectator ions. E)Pb²⁺ and I^- are spectator ions, and PbI₂ will precipitate.

Question

Quizplus · Accepted Answer

Lead(II) iodide (PbI2) is insoluble in water and will precipitate, while potassium (K+) and nitrate (NO3-) ions remain in solution as spectator ions.

Based on the Solubility Rules, Which of the Following Will