The temperature of an ideal gas in a 5.00 L container originally at 1 atm pressure and 25°C is lowered to 220 K. Calculate the new pressure of the gas.
A)1.0 atm
B)1.35 atm
C)8.8 atm
D)0.738 atm
E)0.114 atm

Question

Quizplus · Accepted Answer

We can use the combined gas law to solve for the new pressure:

(P1V1/T1) = (P2V2/T2)

P1 = 1 atm
V1 = 5.00 L
T1 = 25°C = 298 K
T2 = 220 K

Substituting these values and solving for P2:

(1 atm)(5.00 L)/(298 K) = P2(5.00 L)/(220 K)

P2 = (1 atm)(5.00 L)(220 K)/(298 K)(5.00 L) = 0.738 atm

Therefore, the new pressure of the gas is 0.738 atm, which is choice D.

The Temperature of an Ideal Gas in a 5