Calculate the volume of H₂(g)at 273 K and 2.00 atm that will be formed when 275 mL of 0.725 M HCl solution reacts with excess Mg to give hydrogen gas and aqueous magnesium chloride. A)0.56 L B)1.12 L C)2.23 L D)4.47 L E)3.54 L

Question

Quizplus · Accepted Answer

Using the reaction Mg + 2HCl → MgCl₂ + H₂, calculate moles of HCl (0.275 L * 0.725 mol/L = 0.199 mol), which gives 0.0995 mol H₂. Using PV=nRT, V = nRT/P = (0.0995 mol * 0.0821 L·atm/mol·K * 273 K) / 2.00 atm = 1.12 L.

Calculate the Volume of H2(g)at 273 K and 2

Calculate the Volume of H₂(g)at 273 K and 2