Calculate the standard enthalpy of formation of liquid methanol, CH3OH(l) , using the following information: C(graph) + O2 CO2(g) H° = -393.5 kJ/mol
H2(g) + (1/2) O2 H2O(l) H° = -285.8 kJ/mol
CH3OH(l) + (3/2) O2(g) CO2(g) + 2H2O(l) H° = -726.4 kJ/mol
A) -1,691.5 kJ/mol
B) -238.7 kJ/mol
C) 1691.5 kJ/mol
D) 47.1 kJ/mol
E) -47.1 kJ/mol
Correct Answer:
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