What is the percent CsCl by mass in a 0.711 M CsCl solution that has a density of 1.091 g/mL A) 3.87 * 10^-4 % B) 3.87 * 10^-1 % C) 11.0 % D) 1.10 % E) 6.50 * 10^-2 %

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To find the percent by mass of CsCl in the solution, we first need to calculate the mass of CsCl in a given volume of solution and then find the total mass of that volume of solution. The molarity (M) of the solution is given as 0.711 M, which means there are 0.711 moles of CsCl per liter of solution. 1. Calculate the mass of CsCl in 1 liter of solution:The molar mass of CsCl is approximately 168.36 g/mol (Cs = 132.91 g/mol + Cl = 35.45 g/mol). Mass of CsCl = 0.711 moles * 168.36 g/mol = approximately 119.7 g2. Calculate the mass of 1 liter of solution:Since the density of the solution is 1.091 g/mL, the mass of 1 liter (which is 1000 mL) of solution is 1.091 g/mL * 1000 mL = 1091 g.3. Calculate the percent by mass of CsCl in the solution:Percent by mass = (mass of CsCl / mass of solution) * 100 = (119.7 g / 1091 g) * 100 ≈ 11.0%Therefore, the percent by mass of CsCl in the solution is approximately 11.0%.

What Is the Percent CsCl by Mass in a 0