The equilibrium constant expression for the reaction 2BrF5(g) ![The equilibrium constant expression for the reaction 2BrF<sub>5</sub>(g) Br<sub>2</sub>(g) + 5F<sub>2</sub>(g) is A) K<sub>c</sub> = [Br<sub>2</sub>] [F<sub>2</sub>]<sup> </sup>/<sup> </sup>[BrF<sub>5</sub>] B) K<sub>c</sub> = [Br<sub>2</sub>] [F<sub>2</sub>]<sup>5 </sup>/<sup> </sup>[BrF<sub>5</sub>]<sup>2</sup> C) K<sub>c</sub> = [Br<sub>2</sub>] [F<sub>2</sub>]<sup>2 </sup>/<sup> </sup>[BrF<sub>5</sub>]<sup>5</sup> D) K<sub>c</sub> = [BrF<sub>5</sub>]<sup>2 </sup>/<sup> </sup>[Br<sub>2</sub>][F<sub>2</sub>]<sup>5</sup> E) K<sub>c</sub> = 2[BrF<sub>5</sub>]<sup>2 </sup>/<sup> </sup>([Br<sub>2</sub>] * 5[F<sub>2</sub>]<sup>5</sup>)](https://d2lvgg3v3hfg70.cloudfront.net/TB3244/11ea7995_6655_854d_911b_4b21a08d71ee_TB3244_00.jpg)
Br2(g) + 5F2(g) is
A) Kc = [Br2] [F2] / [BrF5]
B) Kc = [Br2] [F2]5 / [BrF5]2
C) Kc = [Br2] [F2]2 / [BrF5]5
D) Kc = [BrF5]2 / [Br2][F2]5
E) Kc = 2[BrF5]2 / ([Br2] * 5[F2]5)
Correct Answer:
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