For the reaction SO₂(g)+ NO₂(g) SO₃(g)+ NO(g), the equilibrium constant is 18.0 at 1,200ºC. If 1.0 mole of SO₂ and 2.0 moles of NO₂ are placed in a 20. L container, what concentration of SO₃ will be present at equilibrium?

Question

Quizplus · Accepted Answer

Using the equilibrium constant expression: Kc = [SO₃][NO] / [SO₂][NO₂]^2 Substituting the values given in the problem: 18.0 = [x][1.0] / [(1.0 - x)(2.0 - 2x)^2] Where x is the concentration (in mol/L) of SO₃ at equilibrium. Simplifying this expression and solving for x with the quadratic formula, we get x = 0.48 mol/L. Therefore, the answer is (A) 0.48 mol/L.

For the Reaction SO2(g)+ NO2(g) SO3(g)+ NO(g), the Equilibrium

For the Reaction SO₂(g)+ NO₂(g) SO₃(g)+ NO(g), the Equilibrium