Calculate the pH of 2.6 *10^-2 M KOH. A) 12.41 B) 15.59 C) 2.06 D) 7.00 E) 1.59

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The concentration of KOH is given as $2.6 \times 10^{-2}$ M. KOH is a strong base that completely dissociates in water, producing $OH^-$ ions. The concentration of $OH^-$ ions is equal to the concentration of KOH, which is $2.6 \times 10^{-2}$ M. To find the pH, we first calculate the pOH using the formula $pOH = -\log[OH^-]$. Then, we use the relationship $pH + pOH = 14$ to find the pH.$$pOH = -\log[2.6 \times 10^{-2}] = 1.59$$$$pH = 14 - pOH = 14 - 1.59 = 12.41$$Therefore, the pH of the solution is 12.41.

Calculate the PH of 2.6 *10-2 M KOH

Calculate the PH of 2.6 *10^-2 M KOH