What is the pH of a 0.001 M Ca(OH)₂ solution A) 3.0 B) 11.0 C) 2.7 D) 17.0 E) 11.3

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Calcium hydroxide, Ca(OH)2, is a strong base that dissociates completely in water to produce two hydroxide ions (OH-) for each formula unit. The concentration of OH- ions in a 0.001 M solution of Ca(OH)2 is therefore 0.002 M. To find the pOH, we use the formula pOH = -log[OH-], which gives pOH = -log(0.002) = 2.7. Since pH + pOH = 14 for aqueous solutions at 25°C, the pH is 14 - 2.7 = 11.3.

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