What is the pH of a solution prepared by mixing 10.0 mL of a strong acid solution with pH = 2.00 and 10.0 mL of a strong acid solution with pH = 6.00?
A)2.0
B)2.3
C)4.0
D)6.0
E)8.0

Question

Quizplus · Accepted Answer

To calculate the pH of the final solution, we need to calculate the concentration of H+ ions in the mixture.

For the first solution: 
pH = -log[H+] 
2.00 = -log[H+] 
[H+] = 10^-2 = 0.01 M

For the second solution: 
pH = -log[H+] 
6.00 = -log[H+] 
[H+] = 10^-6 = 0.000001 M

When we mix these two solutions in equal amounts, we get:

[H+] = (0.01 M + 0.000001 M) / 2 
[H+] = 0.0050005 M

pH = -log[H+] 
pH = -log(0.0050005) 
pH = 2.3

Therefore, the answer is (B) 2.3.

What Is the PH of a Solution Prepared by Mixing