If the measured voltage of the cell Zn(s) | Zn²⁺(aq) || Ag⁺(aq) | Ag(s) is 1.37 V when the concentration of Zn²⁺ ion is 0.010 M, what is the Ag⁺ ion concentration

Question

Quizplus · Accepted Answer

Use the Nernst equation to solve for the concentration of Ag⁺ ion: E = E° - (RT/nF)ln(Q) 1.37 = 0.80 - (0.0257/2)(ln(Q)) ln(Q) = 26.92 Q = [Ag⁺]/[Zn²⁺] 0.010/x = 10^26.92 x = 6.2 x 10^-5 M Therefore, the concentration of Ag⁺ ion is 6.2 x 10^-5 M or 6.2 x 10^(-5+3) = 6.2 x 10^-2 mM or 6.2 x 10^-5 mol/L. The correct answer choice is E.

If the Measured Voltage of the Cell Zn(s) | Zn2+(aq)

If the Measured Voltage of the Cell Zn(s) | Zn²⁺(aq)