Consider the reaction Hg²⁺(aq)+ Hg(l)$\rarr$ Hg₂²⁺(aq). Find the equilibrium constant for this reaction at 25°C.

Question

Quizplus · Accepted Answer

The equilibrium constant expression is Kc = [Hg₂^2]/[][Hg]^3. Since mercury is a liquid and its concentration remains constant, we can write Kc' = [Hg₂^2]/[]. Using stoichiometry, we see that 2 moles of Hg^{2 react with 1 mole of}, so initially the ratio of [Hg₂^2]/[] is 2:1. At equilibrium, this ratio becomes the equilibrium constant Kc'. Therefore, Kc' = 2.

Consider the Reaction Hg2+(aq)+ Hg(l) →\rarr→ Hg22+(aq)

Consider the Reaction Hg²⁺(aq)+ Hg(l) $\rarr$ Hg₂²⁺(aq)