How many moles of BCl₃ are needed to produce 25.0 g of HCl(aq) in the following reaction?
BCl₃(g) + 3 H₂O(l) → 3 HCl(aq) + B(OH) ₃(aq)

Question

How many moles of BCl₃ are needed to produce 25.0 g of HCl(aq)in the following reaction? BCl₃(g)+ 3 H₂O(l)→ 3 HCl(aq)+ B(OH)₃(aq) A)0)229 mol B)0)686 mol C)2)06 mol D)4)38 mol

Quizplus · Accepted Answer

To produce 25.0 g of HCl, we need to use the stoichiometry of the reaction to determine the number of moles of BCl3 required. From the balanced equation, we see that 1 mole of BCl3 produces 3 moles of HCl. Therefore, to produce 25.0 g of HCl, we need:25.0 g HCl x (1 mol HCl / 36.46 g HCl) x (1 mol BCl3 / 3 mol HCl) = 0.229 mol BCl3Therefore, the correct answer is A) 0.229 mol.

How Many Moles of BCl3 Are Needed to Produce 25

How Many Moles of BCl₃ Are Needed to Produce 25