What volume of a 0.540 M NaOH solution contains 11.5 g of NaOH?

Question

Quizplus · Accepted Answer

First, we need to use the molar mass of NaOH to convert the given mass (11.5 g) to moles.

molar mass of NaOH = 40 g/mol
moles of NaOH = mass/molar mass = 11.5 g/40 g/mol = 0.288 mol

Next, we can use the molarity equation (M = moles/volume) to calculate the volume of the solution required to contain 0.288 mol of NaOH at a concentration of 0.540 M.

M = 0.540 M
moles = 0.288 mol
volume = moles/M = 0.288 mol/0.540 M = 0.532 L

Therefore, the answer is B, 0.532 L.

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