A student prepared a stock solution by dissolving 10.0 g of KOH in enough water to make 150.mL of solution.She then took 15.0 mL of the stock solution and diluted it with enough water to make water to make 65.0 mL of a final solution.What is the concentration of KOH for the final solution?

Question

Quizplus · Accepted Answer

The concentration of the stock solution is calculated by dividing the mass of KOH by the molar mass to find moles, then dividing by the volume in liters: (10.0 g / 56.11 g/mol) / 0.150 L = 1.19 M. The final concentration is found by using the dilution formula M1V1 = M2V2: (1.19 M)(0.015 L) = M2(0.065 L), solving for M2 gives 0.274 M.

A Student Prepared a Stock Solution by Dissolving 10