What is the oxidation number of the oxygen atom in Na₂O₂? A)-2 B)-1 C)+1 D)+2

Question

Quizplus · Accepted Answer

In the given compound, Na has a +1 oxidation state and sulfur has a -2 oxidation state. The sum of oxidation states of all elements in a compound is equal to zero. Therefore,
(+1) + 12(-2) + x + 12(-2) + 0 + x + 12(-2) + 0 + 1 + 0 = 0
where x is the oxidation state of the oxygen atom. Solving for x, we get x = -1. Therefore, the oxidation number of the oxygen atom in the given compound is -1, which is option B.

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What Is the Oxidation Number of the Oxygen Atom in Na₂O₂