A basketball is inflated to a pressure of 1.90 atm in a 24.0°C garage.What is the pressure of the basketball outside where the temperature is - 1.00°C?
A)1)74 atm
B)1)80 atm
C)2)00 atm
D)2)08 atm

Question

Quizplus · Accepted Answer

We can use the combined gas law to solve this problem:

(P1/T1) = (P2/T2)

Where P1 is the initial pressure (1.90 atm), T1 is the initial temperature in Kelvin (24.0°C + 273 = 297 K), P2 is the pressure outside the garage, and T2 is the temperature outside in Kelvin (-1.00°C + 273 = 272 K).

Solving for P2, we get:

P2 = (P1/T1) x T2 = (1.90 atm/297 K) x 272 K = 1.738 atm or 1.74 atm (rounded to two significant figures).

Therefore, the best choice is A) 1.74 atm.

A Basketball Is Inflated to a Pressure of 1