Hydroquinone is an antioxidant that is also used as a photographic reducer and developer.The normal boiling point of hydroquinone is 310°C.Calculate the pressure at which hydroquinone will boil at 200°C given that its ΔH_vap is 73.38 kJ/mol. A)1.210 × 10^-4 mm Hg B)1.35 mm Hg C)22.5 mm Hg D)757 mm Hg

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Quizplus · Accepted Answer

First, we need to calculate the ΔHvap of hydroquinone: ΔHvap = ΔH_vap/R = 73.38 kJ/mol / 8.314 J/mol·K = 8832.7 J/mol We can then use the Clausius-Clapeyron equation to find the pressure at 200°C: ln(P2/P1) = -ΔHvap/R * (1/T2 - 1/T1) We assume P1 = 1 atm and T1 = 310°C + 273.15 = 583.15 K T2 = 200°C + 273.15 = 473.15 K Substituting the values and solving for P2, we get: P2 = e^(-ΔHvap/R * (1/T2 - 1/T1)) * P1 = 22.5 mm Hg Therefore, the best choice is C.

Hydroquinone Is an Antioxidant That Is Also Used as a Photographic