Formaldehyde is a carcinogenic volatile organic compound with a permissible exposure level of 0.75 ppm.At this level,how many grams of formaldehyde are permissible in a 6.0-L breath of air having a density of 1.2 kg/m³? A)3.8 × 10^-2 g formaldehyde B)5.4 × 10^-6 g formaldehyde C)3.8 g formaldehyde D)5.4 g formaldehyde

Question

Quizplus · Accepted Answer

First, we need to calculate the mass of the 6.0-L breath of air using the density given:
mass = volume x density = 6.0 L x 1.2 kg/m^3 = 7.2 kg

Next, we can use the permissible exposure level of formaldehyde to find the maximum amount of formaldehyde allowed in this mass of air:
0.75 ppm = 0.75 parts formaldehyde per million parts air
= 0.75/1,000,000 x 7,200 g = 0.0054 g formaldehyde

Therefore, the permissible amount of formaldehyde in a 6.0-L breath of air is 0.0054 g.

The answer is B) 5.4 × 10^-6 g formaldehyde, as this is the closest option to 0.0054 g when expressed in scientific notation.

Formaldehyde Is a Carcinogenic Volatile Organic Compound with a Permissible