A solution is prepared by dissolving 17.75 g sulfuric acid,H₂SO₄,in enough water to make 100.0 mL of solution.If the density of the solution is 1.1094 g/mL,what is the molarity? A)0.1775 M H₂SO₄ B)0.1810 M H₂SO₄ C)1.810 M H₂SO₄ D)1.940 M H₂SO₄

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Quizplus · Accepted Answer

To find molarity, divide moles of solute by liters of solution. Moles of H₂SO₄ = 17.75 g / 98.079 g/mol = 0.1810 mol. Volume of solution = 100.0 mL = 0.1000 L. Molarity = 0.1810 mol / 0.1000 L = 1.810 M.

A Solution Is Prepared by Dissolving 17