The first-order reaction,SO₂Cl₂ → SO₂ + Cl₂,has a rate constant equal to 2.20 × 10^-5 s^-1 at 593 K.What percentage of the initial amount SO₂Cl₂ will remain after 6.00 hours?

Question

Quizplus · Accepted Answer

For a first-order reaction, the remaining concentration can be calculated using the formula: [A] = [A]₀e^(-kt). After calculating using k = 2.20 × 10⁻⁵ s⁻¹ and t = 6 hours (21600 seconds), approximately 62.2% of SO₂Cl₂ remains.

The First-Order Reaction,SO2Cl2 → SO2 + Cl2,has a Rate Constant

The First-Order Reaction,SO₂Cl₂ → SO₂ + Cl₂,has a Rate Constant