If K_c equals 0.11 at 25°C for the reaction: N₂O₄(g)⇌ 2 NO₂(g),what is K_c for the reaction: NO₂(g)⇌ 1/2 N₂O₄(g)?

Question

Quizplus · Accepted Answer

The equilibrium constant for the reverse reaction is the reciprocal of the original reaction's Kc. Additionally, when the stoichiometry is halved, the square root of the reciprocal is taken. Thus, Kc for NO2(g)⇌ 1/2 N2O4(g) is √(1/0.11) ≈ 3.0.

If Kc Equals 0

If K_c Equals 0