Acetic acid CH₃COOH,has an acid dissociation constant of 1.8 × 10^-5.What is the conjugate base of acetic acid and what is its base dissociation constant?

Question

Quizplus · Accepted Answer

The conjugate base of acetic acid (CH3COOH) is acetate ion (CH3COO-), and the base dissociation constant (Kb) can be calculated using the relation Kw = Ka * Kb, where Kw is the ion product of water (1.0 × 10^-14 at 25°C). Given Ka = 1.8 × 10^-5, Kb = Kw / Ka = (1.0 × 10^-14) / (1.8 × 10^-5) = 5.6 × 10^-10.

Acetic Acid CH3COOH,has an Acid Dissociation Constant of 1

Acetic Acid CH₃COOH,has an Acid Dissociation Constant of 1