Ag⁺(aq)+ e^- → Ag(s)E° = +0.800 V AgBr(s)+ e^- → Ag(s)+ Br^-(aq)E° = +0.071 V Br₂(l)+ 2 e^- → 2 Br^-(aq)E° = +1.066 V Use some of the data above to calculate K_sp at 25°C for AgBr.

Question

Quizplus · Accepted Answer

The Ksp for AgBr can be calculated using the Nernst equation and the given standard reduction potentials. The difference in potentials for the dissolution of AgBr is 0.800 V - 0.071 V = 0.729 V. Using the relation ΔG° = -nFE° and ΔG° = -RTlnK, we find Ksp = 10^(-ΔG°/RT) = 10^(-0.729/0.0592) = 4.9 × 10^-13.

Ag+(aq)+ E- → Ag(s)E° = +0.800 V

Ag⁺(aq)+ E^- → Ag(s)E° = +0.800 V