When KO₂ is dissolved in water the evolution of oxygen takes place according to the reaction
2 KO₂(s) + H₂O(l) → O₂(g) + 2 K⁺(aq) + HO₂^-(aq) + OH^-(aq) .In this reaction the O₂^- ion undergoes

Question

Quizplus · Accepted Answer

The O₂^- ion in the reaction is both oxidized and reduced, meaning it undergoes disproportionation. Disproportionation is the simultaneous oxidation and reduction of the same species in a redox reaction. Therefore, Choice A is the best answer.

When KO2 Is Dissolved in Water the Evolution of Oxygen

When KO₂ Is Dissolved in Water the Evolution of Oxygen