How many milliliters of ozone gas at at 25.0°C and 1.00 atm pressure are needed to react with 45.00 mL of a 0.100 M aqueous solution of KI according to the chemical equation shown below?
O₃(g) + 2 I^-(aq) + H₂O(l) → O₂(g) + I₂(s) + 2 OH^-(aq)

Question

Quizplus · Accepted Answer

The reaction requires 1 mole of O3 for every 2 moles of I-. The moles of I- in 45.00 mL of 0.100 M KI is 0.0045 moles. Therefore, 0.00225 moles of O3 are needed. Using the ideal gas law at 25°C and 1 atm, this corresponds to 55.0 mL of O3 gas.

How Many Milliliters of Ozone Gas at At 25