A sample of cesium carbonate,weighing 3.80 g,requires 1.90 g of hydrogen bromide gas to completely decompose to water,cesium bromide,and carbon dioxide gas.The total mass of water and cesium bromide formed is 5.20 g and no hydrogen bromide or cesium carbonate remains.According to the law of conservation of mass,what mass of carbon dioxide must have been formed?

Question

Quizplus · Accepted Answer

The law of conservation of mass states that the mass of the reactants must equal the mass of the products. The total mass of reactants is 3.80 g (cesium carbonate) + 1.90 g (hydrogen bromide) = 5.70 g. The total mass of the products is 5.20 g (water and cesium bromide) + x g (carbon dioxide). To find the mass of carbon dioxide, we subtract the mass of water and cesium bromide from the total mass of reactants: 5.70 g - 5.20 g = 0.50 g.

A Sample of Cesium Carbonate,weighing 3