The specific heat is the amount of heat required to raise the temperature of one gram of a substance one degree Celsius.A 75.0-g sample of an unknown substance absorbed 2.93 kJ of energy as it changed from a temperature of 23.2°C to 95.4°C.What is the specific heat of the unknown substance?
A)541 kJ/(g ⋅°C)
B)0.541 J/(g ⋅°C)
C)5.41 kJ/(g ⋅°C)
D)54.1 kJ/(g ⋅°C)
E)0.541 kJ/(g ⋅°C)

Question

Quizplus · Accepted Answer

The specific heat (c) can be calculated using the formula $c = \frac{q}{m\Delta T}$, where $q$ is the heat absorbed (in joules), $m$ is the mass of the substance (in grams), and $\Delta T$ is the change in temperature (in Celsius). Here, $q = 2.93 kJ = 2930 J$, $m = 75.0 g$, and $\Delta T = 95.4°C - 23.2°C = 72.2°C$. Plugging these values into the formula gives $c = \frac{2930 J}{75.0 g \times 72.2°C} = 0.541 J/(g⋅°C)$.

The Specific Heat Is the Amount of Heat Required to Raise