What is the reduction half-reaction for the reaction of zinc with hydrochloric acid?
Zn(s) + 2H+(aq) + 2Cl-(aq) → Zn2+(aq) + 2Cl-(aq) + H2(g)
A) Zn(s) → Zn2+(aq) + 2e-
B) 2H+(aq) + 2e- → H2(g)
C) 2H+(aq) + 2e-(aq) → H2(g) + 2Cl-(aq)
D) 2H+(aq) + 2Cl-(aq) → H2(g) + 2e- + 2Cl-(aq)
E) Zn(s) → Zn2+(aq) + 2Cl-(aq) + 2e-
Correct Answer:
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