What volume of 0.72 M sodium bromide,NaBr,contains 6.5 × 10^-4 mol of bromide ions?

Question

Quizplus · Accepted Answer

To calculate the required volume of sodium bromide, we need to use the following formula:

n (mol) = M (mol/L) x V (L)

where n is the number of moles of bromide ions, M is the molar concentration of sodium bromide, and V is the volume of sodium bromide.

Rearranging the formula to solve for V, we get:

V = n/M

Substituting the given values, we get:

V = (6.5 × 10^-4 mol) / (0.72 mol/L)
V = 0.0009 L = 0.9 mL

Therefore, the correct answer is C) 0.9 mL.

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