A chemist has a sample of 1.88 M HCl.What volume of the sample does he require to prepare 200 mL of 0.45 M HCl?

Question

Quizplus · Accepted Answer

The formula to use here is:

M1V1 = M2V2

where M1 = initial concentration, V1 = initial volume, M2 = final concentration, and V2 = final volume.

Rearranging the formula to solve for V1:

V1 = (M2V2)/M1

Plugging in the given values:

V1 = (0.45*200)/1.88 = 47.87 mL

Therefore, the chemist would need 47.87 mL of the initial sample to prepare 200 mL of 0.45 M HCl. The best choice is D.

A Chemist Has a Sample of 1