A flexible vessel contains 78.00 L of gas at a pressure of 1.50 atm.Under conditions of constant temperature and moles of gas,what is the pressure of the gas when the volume of the vessel is tripled?
A)0.572 atm
B)4.5111 atm
C)2.38 atm
D)1.5 atm
E)0.025578 atm

Question

Quizplus · Accepted Answer

According to Boyle's Law, PV = constant at constant temperature and moles of gas. Therefore, P1V1 = P2V2.
Given: P1 = 1.5 atm, V1 = 78.00 L, V2 = 3*V1 = 234 L
Therefore, P2 = P1V1/V2 = (1.5 atm * 78.00 L) / 234 L = 0.5 atm = 0.572 atm (rounded to three significant figures). 
Therefore, the best choice is A, which matches this calculation.

A Flexible Vessel Contains 78