What is the standard enthalpy change for the following reaction?
N₂H₄(l) + 2NO₂(g) → 2N₂O(g) + 2H₂O(l)
Substance
ΔH°_f (kJ/mol)
N₂H₄(l)
+50) 6
NO₂(g)
+33) 1
N₂O(g)
+82) 1
H₂O(l)
-285.8

Question

Quizplus · Accepted Answer

The standard enthalpy change is calculated using the formula: ΔH° = ΣΔH°f(products) - ΣΔH°f(reactants). Plugging in the given values: ΔH° = [2(82.1) + 2(-285.8)] - [50.6 + 2(33.1)] = -524.2 kJ.

What Is the Standard Enthalpy Change for the Following Reaction