What is the energy per mole of photons with a wavelength of 307.1 nm? (c=3.00×10⁸ m/s,h=6.63×10^-34 J·s,N_A=6.02×10²³mol^-1) A) 6.48×10^-19 kJ/mol B)1.85×10¹⁴ kJ/mol C)5.88×10³⁵ kJ/mol D)9.77×10¹⁴ kJ/mol E)3.9×10² kJ/mol

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Quizplus · Accepted Answer

The energy of a single photon is calculated using E = hc/λ. Substituting the given values, E = (6.63×10^-34 J·s)(3.00×10^8 m/s) / (307.1×10^-9 m) = 6.48×10^-19 J. To find the energy per mole, multiply by Avogadro's number: (6.48×10^-19 J/photon)(6.02×10^23 photons/mol) = 3.9×10^2 kJ/mol.

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