What is the mass percent of an aqueous sodium hydroxide solution in which the molarity of NaOH is 9.98 M? The density of the solution is 1.33 g/mL.
A)0.1%
B)30.0%
C)13.2%
D)1.7%
E)68.9%

Question

Quizplus · Accepted Answer

To find the mass percent, first calculate the mass of NaOH in 1 liter of solution using its molarity (9.98 mol/L) and molar mass (40 g/mol), which gives 399.2 g. The mass of 1 liter of solution is 1330 g (density 1.33 g/mL). The mass percent is (399.2 g / 1330 g) * 100% = 30.0%.

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