What mass of a solution labeled 6.3% sucrose (C₁₂H₂₂O₁₁,342 g/mol)by mass contains 11.0 g of sucrose?

Question

Quizplus · Accepted Answer

To solve the problem, we need to first calculate the mass of the solution that contains 6.3% sucrose:
Mass of solution = 11.0 g / 0.063 = 174.6 g
Then, we can calculate the mass of sucrose in this solution:
Mass of sucrose = 0.063 x 174.6 g = 11.0 g
Therefore, a mass of 174.6 g of the solution labeled 6.3% sucrose contains 11.0 g of sucrose. Since we are looking for the mass of the solution that contains 11.0 g of sucrose, the answer is:
C) 170 g

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