A second-order reaction starts with an initial concentration of 0.100 mol/L of the reactant.If the rate constant is 2.4× 10^-2 L/(mol ∙ s),what is the time required to decrease the initial concentration to 0.050 mol/L?

Question

Quizplus · Accepted Answer

For a second-order reaction, the time $ t $ required for the concentration of a reactant to change from $ [A]_0 $ to $ [A] $ is given by the equation $\frac{1}{[A]} - \frac{1}{[A]_0} = kt$, where $ k $ is the rate constant. Substituting the given values, $ [A]_0 = 0.100 $ mol/L, $ [A] = 0.050 $ mol/L, and $ k = 2.4 \times 10^{-2} $ L/(mol·s), we get $ t = 410 $ s.

A Second-Order Reaction Starts with an Initial Concentration of 0