What is Kb for the following equilibrium? Ka for HNO2 is 5.0 × 10-4.
NO2-(aq) + H2O(l)
HNO2(aq) + OH-(aq)
A) 2.0 × 10-4
B) 5.0 × 10-4
C) 5.0 × 1010
D) 5.0 × 1018
E) 2.0 × 10-11
Correct Answer:
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