What is K_a for the anilinium cation,C₆H₅NH₃⁺,at 25°C? (K_b for C₆H₅NH₂ = 4.2 × 10^-10 at 25°C.) A)1.0 × 10^-7 B)4.2 × 10⁴ C)4.2 × 10^-24 D)2.4 × 10^-5 E)4.2 × 10^-10

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Quizplus · Accepted Answer

The relationship between K_a and K_b is given by K_w = K_a × K_b, where K_w is the ion product of water (1.0 × 10^-14 at 25°C). Solving for K_a gives K_a = K_w / K_b = (1.0 × 10^-14) / (4.2 × 10^-10) = 2.4 × 10^-5.

What Is Ka for the Anilinium Cation,C6H5NH3+,at 25°C? (Kb for C6H5NH2

What Is K_a for the Anilinium Cation,C₆H₅NH₃⁺,at 25°C? (K_b for C₆H₅NH₂