What is K_c for the following equilibrium? For phosphoric acid (H₃PO₄) ,Ka₁ = 6.9 × 10^-3,Ka₂ = 6.2 × 10^-8,and Ka₃ = 4.8 × 10^-13.
HPO₄^2-(aq) + OH^-(aq)
PO₄^3-(aq) + H₂O(l)

Question

What is K_c for the following equilibrium? For phosphoric acid (H₃PO₄) ,Ka₁ = 6.9 × 10^-3,Ka₂ = 6.2 × 10^-8,and Ka₃ = 4.8 × 10^-13.
HPO₄^2-(aq) + OH^-(aq)

What is K<sub>c</sub> for the following equilibrium? For phosphoric acid (H<sub>3</sub>PO<sub>4</sub>) ,Ka<sub>1</sub> = 6.9 × 10<sup>-3</sup>,Ka<sub>2</sub> = 6.2 × 10<sup>-8</sup>,and Ka<sub>3</sub> = 4.8 × 10<sup>-13</sup>. HPO<sub>4</sub><sup>2-</sup>(aq) + OH<sup>-</sup>(aq) PO<sub>4</sub><sup>3-</sup>(aq) + H<sub>2</sub>O(l) A) 7.3 × 10<sup>-16</sup> B) 6.4 × 10<sup>-23</sup> C) 491 D) 48 E) 2.3 × 10<sup>-35</sup>

PO₄^3-(aq) + H₂O(l)

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The Answer of What is K_c for the following equilibrium? For phosphoric acid (H₃PO₄),Ka₁ = 6.9 × 10^-3,Ka₂ = 6.2 × 10^-8,and Ka₃ = 4.8 × 10^-13. HPO₄^2-(aq)+ OH^-(aq) PO₄^3-(aq)+ H₂O(l) A)7.3 × 10^-16 B)6.4 × 10^-23 C)491 D)48 E)2.3 × 10^-35

What Is Kc for the Following Equilibrium? for Phosphoric Acid

What Is K_c for the Following Equilibrium? for Phosphoric Acid