Titration of 0.2834 g of an unknown monoprotic acid dissolved in 25.00 mL of water requires 29.83 mL of 0.1582 M NaOH to reach the endpoint.What is the molar mass of the acid?

Question

Quizplus · Accepted Answer

The correct answer is A because the molar mass of the acid can be calculated using the formula: Molar mass = (Mass of acid / Volume of NaOH in liters) x (Molarity of NaOH) x (Volume of NaOH in mL) / (Volume of acid in mL)= (0.2834 g / 0.02983 L) x (0.1582 M) x (29.83 mL) / (25.00 mL)= 60 g/mol