What is the solubility (in g/L)of silver(I)chloride at 25°C? The solubility product constant for silver(I)chloride is 1.8 × 10^-10 at 25°C. A)5.1 × 10^-2 g/L B)2.6 × 10^-8 g/L C)1.9 × 10^-3 g/L D)1.3 × 10^-8 g/L E)2.6 × 10^-1 g/L

Question

Quizplus · Accepted Answer

Using the solubility product constant (Ksp) equation:
Ksp = [Ag+][Cl-]
Let x be the solubility of AgCl in g/L
Then, at equilibrium:
[Ag+] = x mol/L
[Cl-] = x mol/L
Substituting,
1.8 × 10^-10 = x^2
x = √(1.8 × 10^-10) = 1.3 × 10^-5 mol/L
Converting to g/L by multiplying with molar mass of AgCl (143.32 g/mol), we get:
x = 1.3 × 10^-5 * 143.32 = 1.86 × 10^-3 g/L, which is approximately 1.9 × 10^-3 g/L. 
Therefore, the solubility of AgCl at 25°C is 1.9 × 10^-3 g/L, which is closest to option C.

What Is the Solubility (In G/L)of Silver(I)chloride at 25°C? the Solubility