What is the molar solubility of aluminum hydroxide at 25°C? The solubility product constant for aluminum hydroxide is 4.6 × 10^-33 at 25°C.

Question

Quizplus · Accepted Answer

The molar solubility of aluminum hydroxide can be calculated using the solubility product constant (Ksp) expression:Ksp = [Al3+][OH-]3At equilibrium, the molar solubility of aluminum hydroxide (s) is equal to the concentration of aluminum ions ([Al3+]) in solution. Substituting the Ksp value and solving for [Al3+], we get:[Al3+] = (Ksp/[OH-]3)^(1/4)Assuming that the hydroxide ion concentration ([OH-]) is negligible compared to the solubility of aluminum hydroxide, we can approximate [OH-] ≈ 2s. Substituting this into the equation, we get:[Al3+] ≈ (4.6 × 10^-33/(2s)^3)^(1/4)Solving for s, we get:s ≈ 3.6 × 10^-9 MTherefore, the molar solubility of aluminum hydroxide at 25°C is approximately 3.6 × 10^-9 M.

What Is the Molar Solubility of Aluminum Hydroxide at 25°C