How many moles of CaF₂ will dissolve in 3.0 L of 0.041 M NaF solution? (K_sp for CaF₂ = 4.0 × 10^-11)

Question

Quizplus · Accepted Answer

Using the equation for the solubility product, we can calculate the amount of CaF₂ that will dissolve in the NaF solution: K_sp = [Ca2+][F-]^2 4.0 × 10^-11 = [CaF₂][2(0.041 M)] [CaF₂] = (4.0 × 10^-11) / (0.082 M) [CaF₂] = 4.88 × 10^-10 mol/L Multiplying the concentration by the volume of the solution: [CaF₂] x 3.0 L = 1.46 × 10^-8 mol Therefore, the answer is C) 7.1 × 10^-8.

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How Many Moles of CaF₂ Will Dissolve in 3