Consider the following reaction: 2C(s)+ 2H₂(g)→ C₂H₄(g); ΔH° = 52.47 kJ; ΔS° = -53.5 J/K at 298 K What is the equilibrium constant at 298 K for this reaction?

Question

Quizplus · Accepted Answer

The equilibrium constant (K) can be calculated using the Gibbs free energy change (ΔG°) at 298 K:ΔG° = -RTlnKΔG° = ΔH° - TΔS°ΔG° = (52.47 kJ/mol) - (298 K)(-53.5 J/K/mol) = 104.9 kJ/molK = e^(-ΔG°/RT) = e^(-104.9 kJ/mol / (8.314 J/K/mol * 298 K)) = 1.0 × 10^-12

Consider the Following Reaction