Using a normal curve table,if a person has a music aptitude score of 41,which equals a Z score of 1.3,the percentage of people having a higher score is
A)40.32% − 50% = -9.68%
B)50% − 40.32% = 9.68%
C)100% − 40.32% = 59.68%
D)50% + 40.32% = 90.32%

Question

Quizplus · Accepted Answer

Using a normal curve table, we find that a Z score of 1.3 corresponds to an area of 0.9032. This means that 90.32% of people have a music aptitude score lower than 41. To find the percentage of people with a higher score, we subtract this value from 50% (since the normal curve is symmetrical).

50% - 40.32% = 9.68%

Therefore, the percentage of people with a higher score is 9.68%.

Using a Normal Curve Table,if a Person Has a Music