A bird,accelerating from rest at a constant rate,experiences a displacement of 37 m in 11 s.What is the final velocity after 11 s?
A) 6.7 m/s
B) 5.1 m/s
C) 13 m/s
D) zero

Question

Quizplus · Accepted Answer

Using the equation of motion: $ s = ut + \frac{1}{2}at^2 $, where $ s = 37 \, \text{m} $, $ u = 0 \, \text{m/s} $, and $ t = 11 \, \text{s} $. Solving for $ a $, we get $ a = \frac{2s}{t^2} = \frac{2 \times 37}{11^2} \approx 0.61 \, \text{m/s}^2 $. The final velocity $ v = u + at = 0 + 0.61 \times 11 \approx 6.7 \, \text{m/s} $.

A Bird,accelerating from Rest at a Constant Rate,experiences a Displacement