A Cessna aircraft has a lift-off speed of 120 km/hr.What minimum constant acceleration does this require if the aircraft is to be airborne after a take-off run of 270 m?

Question

A Cessna aircraft has a lift-off speed of 120 km/hr.What minimum constant acceleration does this require if the aircraft is to be airborne after a take-off run of 270 m?
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Quizplus · Accepted Answer

To find the minimum constant acceleration, use the equation $ v^2 = u^2 + 2as $, where $ v = 120 $ km/hr = 33.33 m/s (converted), $ u = 0 $ m/s (initial speed), and $ s = 270 $ m. Solving for $ a $, we get $ a = \frac{v^2}{2s} = \frac{(33.33)^2}{2 \times 270} \approx 2.06 $ m/s².

A Cessna Aircraft Has a Lift-Off Speed of 120 Km/hr