Jack pulls a sled across a level field by exerting a force of 110 N at an angle of 30° with the ground.What are the parallel and perpendicular components,respectively,of this force with respect to the ground?
A) 190 N,110 N
B) 110 N,190 N
C) 95 N,55 N
D) 55 N,95 N
E) 64 N,191 N

Question

Jack pulls a sled across a level field by exerting a force of 110 N at an angle of 30° with the ground.What are the parallel and perpendicular components,respectively,of this force with respect to the ground?​
A) 190 N,110 N
B) 110 N,190 N
C) 95 N,55 N
D) 55 N,95 N
E) ​64 N,191 N

Quizplus · Accepted Answer

To determine the parallel and perpendicular components of the force exerted by Jack, we can use trigonometry:

The parallel component is given by Fp = Fcosθ, where F is the magnitude of the force (110 N) and θ is the angle that the force makes with the ground (30°).

Fp = 110 N × cos 30° 
Fp = 110 N × 0.866 
Fp = 95 N

The perpendicular component is given by Fp = Fsinθ.

Fp = 110 N × sin 30° 
Fp = 110 N × 0.5 
Fp = 55 N

Therefore, the parallel component is 95 N and the perpendicular component is 55 N. The correct answer is C.

Jack Pulls a Sled Across a Level Field by Exerting